Base | Representation |
---|---|
bin | 110110001011000000… |
… | …0100011110100100111 |
3 | 102010021110202010101111 |
4 | 1230112000203310213 |
5 | 3401222320044341 |
6 | 125235351405451 |
7 | 11255564160034 |
oct | 1542600436447 |
9 | 363243663344 |
10 | 116333362471 |
11 | 45378172077 |
12 | 1a667983887 |
13 | ac7c675071 |
14 | 58b83ac38b |
15 | 305d12e681 |
hex | 1b16023d27 |
116333362471 has 4 divisors (see below), whose sum is σ = 116845844472. Its totient is φ = 115820880472.
The previous prime is 116333362451. The next prime is 116333362477. The reversal of 116333362471 is 174263333611.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 116333362471 - 29 = 116333361959 is a prime.
It is a super-3 number, since 3×1163333624713 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (116333362477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 256240660 + ... + 256241113.
It is an arithmetic number, because the mean of its divisors is an integer number (29211461118).
Almost surely, 2116333362471 is an apocalyptic number.
116333362471 is a deficient number, since it is larger than the sum of its proper divisors (512482001).
116333362471 is an equidigital number, since it uses as much as digits as its factorization.
116333362471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 512482000.
The product of its digits is 163296, while the sum is 40.
The spelling of 116333362471 in words is "one hundred sixteen billion, three hundred thirty-three million, three hundred sixty-two thousand, four hundred seventy-one".
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