11634035311133 has 4 divisors (see below), whose sum is σ = 11670735738300. Its totient is φ = 11597334883968.

The previous prime is 11634035311103. The next prime is 11634035311153. The reversal of 11634035311133 is 33111353043611.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 844932316804 + 10789102994329 = 919202^2 + 3284677^2 .

It is a cyclic number.

It is not a de Polignac number, because 11634035311133 - 2⁴⁰ = 10534523683357 is a prime.

It is a super-2 number, since 2×11634035311133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11634035311093 and 11634035311102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11634035311103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18350213108 + ... + 18350213741.

It is an arithmetic number, because the mean of its divisors is an integer number (2917683934575).

Almost surely, 2^{11634035311133} is an apocalyptic number.

It is an amenable number.

11634035311133 is a deficient number, since it is larger than the sum of its proper divisors (36700427167).

11634035311133 is an equidigital number, since it uses as much as digits as its factorization.

11634035311133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36700427166.

The product of its (nonzero) digits is 29160, while the sum is 35.

Adding to 11634035311133 its reverse (33111353043611), we get a palindrome (44745388354744).

The spelling of 11634035311133 in words is "eleven trillion, six hundred thirty-four billion, thirty-five million, three hundred eleven thousand, one hundred thirty-three".