Base | Representation |
---|---|
bin | 10000111011100101000… |
… | …111111110110100001001 |
3 | 11010020011021202100101022 |
4 | 100323211013332310021 |
5 | 123030304210312211 |
6 | 2250255302402225 |
7 | 150026151255314 |
oct | 20734507766411 |
9 | 4106137670338 |
10 | 1163485244681 |
11 | 4094820a7a61 |
12 | 1695a8a30375 |
13 | 85940606906 |
14 | 40454b9797b |
15 | 203e9198bdb |
hex | 10ee51fed09 |
1163485244681 has 4 divisors (see below), whose sum is σ = 1163564027664. Its totient is φ = 1163406461700.
The previous prime is 1163485244639. The next prime is 1163485244683. The reversal of 1163485244681 is 1864425843611.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1163485244681 is a prime.
It is a super-2 number, since 2×11634852446812 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1163485244683) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39369335 + ... + 39398876.
It is an arithmetic number, because the mean of its divisors is an integer number (290891006916).
Almost surely, 21163485244681 is an apocalyptic number.
It is an amenable number.
1163485244681 is a deficient number, since it is larger than the sum of its proper divisors (78782983).
1163485244681 is an equidigital number, since it uses as much as digits as its factorization.
1163485244681 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78782982.
The product of its digits is 4423680, while the sum is 53.
The spelling of 1163485244681 in words is "one trillion, one hundred sixty-three billion, four hundred eighty-five million, two hundred forty-four thousand, six hundred eighty-one".
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