116433153301 has 4 divisors (see below), whose sum is σ = 120189061504. Its totient is φ = 112677245100.

The previous prime is 116433153283. The next prime is 116433153427. The reversal of 116433153301 is 103351334611.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 116433153301 - 2¹³ = 116433145109 is a prime.

It is a super-2 number, since 2×116433153301² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (31), and also a Moran number because the ratio is a prime number: 3755908171 = 116433153301 / (1 + 1 + 6 + 4 + 3 + 3 + 1 + 5 + 3 + 3 + 0 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (116433153101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1877954055 + ... + 1877954116.

It is an arithmetic number, because the mean of its divisors is an integer number (30047265376).

Almost surely, 2^116433153301 is an apocalyptic number.

It is an amenable number.

116433153301 is a deficient number, since it is larger than the sum of its proper divisors (3755908203).

116433153301 is an equidigital number, since it uses as much as digits as its factorization.

116433153301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3755908202.

The product of its (nonzero) digits is 9720, while the sum is 31.

Adding to 116433153301 its reverse (103351334611), we get a palindrome (219784487912).

The spelling of 116433153301 in words is "one hundred sixteen billion, four hundred thirty-three million, one hundred fifty-three thousand, three hundred one".