116433231301 has 4 divisors (see below), whose sum is σ = 117076509004. Its totient is φ = 115789953600.

The previous prime is 116433231253. The next prime is 116433231349. The reversal of 116433231301 is 103132334611.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 103132334611 = 73 ⋅1412771707.

It is an interprime number because it is at equal distance from previous prime (116433231253) and next prime (116433231349).

It can be written as a sum of positive squares in 2 ways, for example, as 11188139076 + 105245092225 = 105774^2 + 324415^2 .

It is a cyclic number.

It is not a de Polignac number, because 116433231301 - 2¹⁵ = 116433198533 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 116433231301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (116433231391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 321638580 + ... + 321638941.

It is an arithmetic number, because the mean of its divisors is an integer number (29269127251).

Almost surely, 2^116433231301 is an apocalyptic number.

It is an amenable number.

116433231301 is a deficient number, since it is larger than the sum of its proper divisors (643277703).

116433231301 is an equidigital number, since it uses as much as digits as its factorization.

116433231301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 643277702.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 116433231301 its reverse (103132334611), we get a palindrome (219565565912).

The spelling of 116433231301 in words is "one hundred sixteen billion, four hundred thirty-three million, two hundred thirty-one thousand, three hundred one".