Search a number
-
+
11653674113 = 21155230683
BaseRepresentation
bin10101101101001110…
…01111010010000001
31010002011102222112202
422312213033102001
5142331320032423
65204214402545
7561534411164
oct126647172201
933064388482
1011653674113
114a40216934
122312960455
131139496a73
147c7a29adb
15483160728
hex2b69cf481

11653674113 has 4 divisors (see below), whose sum is σ = 11708905008. Its totient is φ = 11598443220.

The previous prime is 11653674091. The next prime is 11653674119. The reversal of 11653674113 is 31147635611.

11653674113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11653674113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11653674119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27615131 + ... + 27615552.

It is an arithmetic number, because the mean of its divisors is an integer number (2927226252).

Almost surely, 211653674113 is an apocalyptic number.

It is an amenable number.

11653674113 is a deficient number, since it is larger than the sum of its proper divisors (55230895).

11653674113 is an equidigital number, since it uses as much as digits as its factorization.

11653674113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55230894.

The product of its digits is 45360, while the sum is 38.

The spelling of 11653674113 in words is "eleven billion, six hundred fifty-three million, six hundred seventy-four thousand, one hundred thirteen".

Divisors: 1 211 55230683 11653674113