11673483555903 has 16 divisors (see below), whose sum is σ = 16762003601280. Its totient is φ = 7183648547424.

The previous prime is 11673483555869. The next prime is 11673483555911. The reversal of 11673483555903 is 30955538437611.

It is a Cunningham number, because it is equal to 3416648²-1.

It is not a de Polignac number, because 11673483555903 - 2¹⁰ = 11673483554879 is a prime.

It is a super-2 number, since 2×11673483555903² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11673483553903) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9680500 + ... + 10819382.

It is an arithmetic number, because the mean of its divisors is an integer number (1047625225080).

Almost surely, 2^{11673483555903} is an apocalyptic number.

11673483555903 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

11673483555903 is a deficient number, since it is larger than the sum of its proper divisors (5088520045377).

11673483555903 is a wasteful number, since it uses less digits than its factorization.

11673483555903 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1401718.

The product of its (nonzero) digits is 40824000, while the sum is 60.

The spelling of 11673483555903 in words is "eleven trillion, six hundred seventy-three billion, four hundred eighty-three million, five hundred fifty-five thousand, nine hundred three".