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11704491350141 = 234791062402773
BaseRepresentation
bin1010101001010010101000…
…0011001001100001111101
31112102221100010102022011212
42222110222003021201331
53013231244241201031
640520545154054205
72315423130643202
oct252245203114175
945387303368155
1011704491350141
113802935260427
1213904aa57a365
1366b962229615
142c6701173ca9
151546d9be212b
hexaa52a0c987d

11704491350141 has 8 divisors (see below), whose sum is σ = 12238879956480. Its totient is φ = 11172227550352.

The previous prime is 11704491350129. The next prime is 11704491350159. The reversal of 11704491350141 is 14105319440711.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11704491350141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11704491350171) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 531190370 + ... + 531212403.

It is an arithmetic number, because the mean of its divisors is an integer number (1529859994560).

Almost surely, 211704491350141 is an apocalyptic number.

It is an amenable number.

11704491350141 is a deficient number, since it is larger than the sum of its proper divisors (534388606339).

11704491350141 is a wasteful number, since it uses less digits than its factorization.

11704491350141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1062403275.

The product of its (nonzero) digits is 60480, while the sum is 41.

The spelling of 11704491350141 in words is "eleven trillion, seven hundred four billion, four hundred ninety-one million, three hundred fifty thousand, one hundred forty-one".

Divisors: 1 23 479 11017 1062402773 24435263779 508890928267 11704491350141