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11705053 = 19161283
BaseRepresentation
bin101100101001…
…101011011101
3211000200022111
4230221223131
510444030203
61054514021
7201330343
oct54515335
924020274
1011705053
1166751a8
123b05911
13256a989
1417a9993
15106326d
hexb29add

11705053 has 4 divisors (see below), whose sum is σ = 11766528. Its totient is φ = 11643580.

The previous prime is 11705041. The next prime is 11705077. The reversal of 11705053 is 35050711.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35050711 = 293119627.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11705053 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11705033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30451 + ... + 30832.

It is an arithmetic number, because the mean of its divisors is an integer number (2941632).

Almost surely, 211705053 is an apocalyptic number.

It is an amenable number.

11705053 is a deficient number, since it is larger than the sum of its proper divisors (61475).

11705053 is an equidigital number, since it uses as much as digits as its factorization.

11705053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61474.

The product of its (nonzero) digits is 525, while the sum is 22.

The square root of 11705053 is about 3421.2648245934. The cubic root of 11705053 is about 227.0515450233.

Adding to 11705053 its reverse (35050711), we get a palindrome (46755764).

The spelling of 11705053 in words is "eleven million, seven hundred five thousand, fifty-three".

Divisors: 1 191 61283 11705053