Base | Representation |
---|---|
bin | 110110100000011110… |
… | …1110000011111011010 |
3 | 102012010200211202101012 |
4 | 1231000331300133122 |
5 | 3404211314020333 |
6 | 125435054253522 |
7 | 11312464664462 |
oct | 1550075603732 |
9 | 365120752335 |
10 | 117054048218 |
11 | 45707a5aa28 |
12 | 1a8291b72a2 |
13 | b065a77a33 |
14 | 5945dacba2 |
15 | 30a153ae48 |
hex | 1b40f707da |
117054048218 has 4 divisors (see below), whose sum is σ = 175581072330. Its totient is φ = 58527024108.
The previous prime is 117054048173. The next prime is 117054048247. The reversal of 117054048218 is 812840450711.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 109384317289 + 7669730929 = 330733^2 + 87577^2 .
It is a Curzon number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 29263512053 + ... + 29263512056.
Almost surely, 2117054048218 is an apocalyptic number.
117054048218 is a deficient number, since it is larger than the sum of its proper divisors (58527024112).
117054048218 is an equidigital number, since it uses as much as digits as its factorization.
117054048218 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58527024111.
The product of its (nonzero) digits is 71680, while the sum is 41.
Adding to 117054048218 its reverse (812840450711), we get a palindrome (929894498929).
The spelling of 117054048218 in words is "one hundred seventeen billion, fifty-four million, forty-eight thousand, two hundred eighteen".
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