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11712195431 = 101115962331
BaseRepresentation
bin10101110100001100…
…11110101101100111
31010020020120011200222
422322012132231213
5142441310223211
65214104554555
7563145006236
oct127206365547
933206504628
1011712195431
114a70257862
12232a482a5b
131148646971
147d1700b1d
154883701db
hex2ba19eb67

11712195431 has 4 divisors (see below), whose sum is σ = 11828157864. Its totient is φ = 11596233000.

The previous prime is 11712195421. The next prime is 11712195463. The reversal of 11712195431 is 13459121711.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11712195431 - 218 = 11711933287 is a prime.

It is a super-2 number, since 2×117121954312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11712195391 and 11712195400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11712195421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57981065 + ... + 57981266.

It is an arithmetic number, because the mean of its divisors is an integer number (2957039466).

Almost surely, 211712195431 is an apocalyptic number.

11712195431 is a deficient number, since it is larger than the sum of its proper divisors (115962433).

11712195431 is a wasteful number, since it uses less digits than its factorization.

11712195431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 115962432.

The product of its digits is 7560, while the sum is 35.

The spelling of 11712195431 in words is "eleven billion, seven hundred twelve million, one hundred ninety-five thousand, four hundred thirty-one".

Divisors: 1 101 115962331 11712195431