Base | Representation |
---|---|
bin | 11010101000101100000001… |
… | …111110110001111111110111 |
3 | 120100202222102000120000021121 |
4 | 122220230001332301333313 |
5 | 110323302001123431320 |
6 | 1053051443052524411 |
7 | 33450315621426244 |
oct | 3250540176617767 |
9 | 510688360500247 |
10 | 117145266233335 |
11 | 343650348aa72a |
12 | 1117b654780707 |
13 | 504999c524b72 |
14 | 20cdc0ad6a5cb |
15 | d8233d1288aa |
hex | 6a8b01fb1ff7 |
117145266233335 has 4 divisors (see below), whose sum is σ = 140574319480008. Its totient is φ = 93716212986664.
The previous prime is 117145266233243. The next prime is 117145266233353. The reversal of 117145266233335 is 533332662541711.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 117145266233335 - 219 = 117145265709047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11714526623329 + ... + 11714526623338.
It is an arithmetic number, because the mean of its divisors is an integer number (35143579870002).
Almost surely, 2117145266233335 is an apocalyptic number.
117145266233335 is a deficient number, since it is larger than the sum of its proper divisors (23429053246673).
117145266233335 is an equidigital number, since it uses as much as digits as its factorization.
117145266233335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23429053246672.
The product of its digits is 8164800, while the sum is 52.
The spelling of 117145266233335 in words is "one hundred seventeen trillion, one hundred forty-five billion, two hundred sixty-six million, two hundred thirty-three thousand, three hundred thirty-five".
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