Base | Representation |
---|---|
bin | 110110100011101011… |
… | …1100100010100001011 |
3 | 102012102011222201111022 |
4 | 1231013113210110023 |
5 | 3404421314234022 |
6 | 125453453023055 |
7 | 11315241061163 |
oct | 1550727442413 |
9 | 365364881438 |
10 | 117161477387 |
11 | 45762666069 |
12 | 1a859184a8b |
13 | b0820bcba6 |
14 | 59563755a3 |
15 | 30aababc42 |
hex | 1b475e450b |
117161477387 has 4 divisors (see below), whose sum is σ = 124053329016. Its totient is φ = 110269625760.
The previous prime is 117161477359. The next prime is 117161477467. The reversal of 117161477387 is 783774161711.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 117161477387 - 212 = 117161473291 is a prime.
It is not an unprimeable number, because it can be changed into a prime (117161477357) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3445925789 + ... + 3445925822.
It is an arithmetic number, because the mean of its divisors is an integer number (31013332254).
Almost surely, 2117161477387 is an apocalyptic number.
117161477387 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
117161477387 is a deficient number, since it is larger than the sum of its proper divisors (6891851629).
117161477387 is an equidigital number, since it uses as much as digits as its factorization.
117161477387 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6891851628.
The product of its digits is 1382976, while the sum is 53.
The spelling of 117161477387 in words is "one hundred seventeen billion, one hundred sixty-one million, four hundred seventy-seven thousand, three hundred eighty-seven".
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