Base | Representation |
---|---|
bin | 10101110100110000… |
… | …11110001101111010 |
3 | 1010020120102210121111 |
4 | 22322120132031322 |
5 | 142444012140434 |
6 | 5214354030534 |
7 | 563233052164 |
oct | 127230361572 |
9 | 33216383544 |
10 | 11716911994 |
11 | 4a72989447 |
12 | 232bb7844a |
13 | 1149608728 |
14 | 7d21ab934 |
15 | 4889a2964 |
hex | 2ba61e37a |
11716911994 has 4 divisors (see below), whose sum is σ = 17575367994. Its totient is φ = 5858455996.
The previous prime is 11716911991. The next prime is 11716912007. The reversal of 11716911994 is 49911961711.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 49911961711 = 31 ⋅1610063281.
It can be written as a sum of positive squares in only one way, i.e., 11489052969 + 227859025 = 107187^2 + 15095^2 .
It is a super-3 number, since 3×117169119943 (a number of 31 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11716911991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2929227997 + ... + 2929228000.
Almost surely, 211716911994 is an apocalyptic number.
11716911994 is a deficient number, since it is larger than the sum of its proper divisors (5858456000).
11716911994 is an equidigital number, since it uses as much as digits as its factorization.
11716911994 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5858455999.
The product of its digits is 122472, while the sum is 49.
The spelling of 11716911994 in words is "eleven billion, seven hundred sixteen million, nine hundred eleven thousand, nine hundred ninety-four".
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