Base | Representation |
---|---|
bin | 10101110110100100… |
… | …10010111010100101 |
3 | 1010021121221220120002 |
4 | 22323102102322211 |
5 | 143011402220203 |
6 | 5220054551045 |
7 | 563505643604 |
oct | 127322227245 |
9 | 33247856502 |
10 | 11732070053 |
11 | 4a804a1970 |
12 | 2335068485 |
13 | 114c7b4cb2 |
14 | 7d41d5a3b |
15 | 489e98d88 |
hex | 2bb492ea5 |
11732070053 has 4 divisors (see below), whose sum is σ = 12798621888. Its totient is φ = 10665518220.
The previous prime is 11732070047. The next prime is 11732070061. The reversal of 11732070053 is 35007023711.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11732070053 - 218 = 11731807909 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 11732069998 and 11732070025.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11732070013) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 533275901 + ... + 533275922.
It is an arithmetic number, because the mean of its divisors is an integer number (3199655472).
Almost surely, 211732070053 is an apocalyptic number.
It is an amenable number.
11732070053 is a deficient number, since it is larger than the sum of its proper divisors (1066551835).
11732070053 is a wasteful number, since it uses less digits than its factorization.
11732070053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1066551834.
The product of its (nonzero) digits is 4410, while the sum is 29.
Adding to 11732070053 its reverse (35007023711), we get a palindrome (46739093764).
The spelling of 11732070053 in words is "eleven billion, seven hundred thirty-two million, seventy thousand, fifty-three".
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