Base | Representation |
---|---|
bin | 110110101000110010… |
… | …0000000101001001011 |
3 | 102012212002211010220221 |
4 | 1231101210000221023 |
5 | 3410244110330212 |
6 | 125522442530511 |
7 | 11322415614304 |
oct | 1552144005113 |
9 | 365762733827 |
10 | 117332511307 |
11 | 45840164410 |
12 | 1a8a6506a37 |
13 | b0ab6749ab |
14 | 5970d777ab |
15 | 30babe3807 |
hex | 1b51900a4b |
117332511307 has 4 divisors (see below), whose sum is σ = 127999103256. Its totient is φ = 106665919360.
The previous prime is 117332511281. The next prime is 117332511311. The reversal of 117332511307 is 703115233711.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 703115233711 = 11 ⋅63919566701.
It is not a de Polignac number, because 117332511307 - 215 = 117332478539 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (117332511407) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5333295958 + ... + 5333295979.
It is an arithmetic number, because the mean of its divisors is an integer number (31999775814).
Almost surely, 2117332511307 is an apocalyptic number.
117332511307 is a deficient number, since it is larger than the sum of its proper divisors (10666591949).
117332511307 is a wasteful number, since it uses less digits than its factorization.
117332511307 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10666591948.
The product of its (nonzero) digits is 13230, while the sum is 34.
The spelling of 117332511307 in words is "one hundred seventeen billion, three hundred thirty-two million, five hundred eleven thousand, three hundred seven".
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