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11733345122234 = 26079665028931
BaseRepresentation
bin1010101010111110000111…
…0111100011011110111010
31112112200210222212210110112
42222233201313203132322
53014214342322402414
640542120242344322
72320464141651551
oct252574167433672
945480728783415
1011733345122234
1138140a148546a
12139600165b0a2
136715acca6548
142c7c7b288d98
15155327da2d3e
hexaabe1de37ba

11733345122234 has 8 divisors (see below), whose sum is σ = 17629012771968. Its totient is φ = 5857007531580.

The previous prime is 11733345122203. The next prime is 11733345122237. The reversal of 11733345122234 is 43222154333711.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11733345122191 and 11733345122200.

It is not an unprimeable number, because it can be changed into a prime (11733345122237) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4832513252 + ... + 4832515679.

It is an arithmetic number, because the mean of its divisors is an integer number (2203626596496).

Almost surely, 211733345122234 is an apocalyptic number.

11733345122234 is a deficient number, since it is larger than the sum of its proper divisors (5895667649734).

11733345122234 is an equidigital number, since it uses as much as digits as its factorization.

11733345122234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9665029540.

The product of its digits is 362880, while the sum is 41.

Adding to 11733345122234 its reverse (43222154333711), we get a palindrome (54955499455945).

The spelling of 11733345122234 in words is "eleven trillion, seven hundred thirty-three billion, three hundred forty-five million, one hundred twenty-two thousand, two hundred thirty-four".

Divisors: 1 2 607 1214 9665028931 19330057862 5866672561117 11733345122234