Base | Representation |
---|---|
bin | 11010101110101001101110… |
… | …101100010011111001010001 |
3 | 120102020011021212200012112222 |
4 | 122232221232230103321101 |
5 | 110402010332133013410 |
6 | 1054004023430030425 |
7 | 33522035156114462 |
oct | 3256515654237121 |
9 | 512204255605488 |
10 | 117555112001105 |
11 | 34502930084089 |
12 | 11226b751a8415 |
13 | 50795268cc29c |
14 | 21059aa9c4d69 |
15 | d8cd290b6955 |
hex | 6aea6eb13e51 |
117555112001105 has 24 divisors (see below), whose sum is σ = 147488211487680. Its totient is φ = 89941734257760.
The previous prime is 117555112001027. The next prime is 117555112001147. The reversal of 117555112001105 is 501100211555711.
It is a de Polignac number, because none of the positive numbers 2k-117555112001105 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 14338790 + ... + 20993120.
It is an arithmetic number, because the mean of its divisors is an integer number (6145342145320).
Almost surely, 2117555112001105 is an apocalyptic number.
It is an amenable number.
117555112001105 is a deficient number, since it is larger than the sum of its proper divisors (29933099486575).
117555112001105 is an equidigital number, since it uses as much as digits as its factorization.
117555112001105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6661061 (or 6661038 counting only the distinct ones).
The product of its (nonzero) digits is 8750, while the sum is 35.
Adding to 117555112001105 its reverse (501100211555711), we get a palindrome (618655323556816).
The spelling of 117555112001105 in words is "one hundred seventeen trillion, five hundred fifty-five billion, one hundred twelve million, one thousand, one hundred five".
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