Base | Representation |
---|---|
bin | 10101111010111010… |
… | …00110000101101101 |
3 | 1010101011102111001110 |
4 | 22331131012011231 |
5 | 143100211034113 |
6 | 5223434502233 |
7 | 564430135662 |
oct | 127535060555 |
9 | 33334374043 |
10 | 11768455533 |
11 | 4a99a9390a |
12 | 2345294979 |
13 | 11571b4573 |
14 | 7d8d87a69 |
15 | 48d284bc3 |
hex | 2bd74616d |
11768455533 has 4 divisors (see below), whose sum is σ = 15691274048. Its totient is φ = 7845637020.
The previous prime is 11768455499. The next prime is 11768455571. The reversal of 11768455533 is 33555486711.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33555486711 = 3 ⋅11185162237.
It is not a de Polignac number, because 11768455533 - 212 = 11768451437 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11768455583) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1961409253 + ... + 1961409258.
It is an arithmetic number, because the mean of its divisors is an integer number (3922818512).
Almost surely, 211768455533 is an apocalyptic number.
It is an amenable number.
11768455533 is a deficient number, since it is larger than the sum of its proper divisors (3922818515).
11768455533 is an equidigital number, since it uses as much as digits as its factorization.
11768455533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3922818514.
The product of its digits is 1512000, while the sum is 48.
The spelling of 11768455533 in words is "eleven billion, seven hundred sixty-eight million, four hundred fifty-five thousand, five hundred thirty-three".
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