118113763506181 has 4 divisors (see below), whose sum is σ = 118116095654752. Its totient is φ = 118111431357612.

The previous prime is 118113763506139. The next prime is 118113763506187. The reversal of 118113763506181 is 181605367311811.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 118113763506181 - 2¹⁵ = 118113763473413 is a prime.

It is a super-2 number, since 2×118113763506181² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (118113763506187) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1165998315 + ... + 1166099608.

It is an arithmetic number, because the mean of its divisors is an integer number (29529023913688).

Almost surely, 2^{118113763506181} is an apocalyptic number.

It is an amenable number.

118113763506181 is a deficient number, since it is larger than the sum of its proper divisors (2332148571).

118113763506181 is an equidigital number, since it uses as much as digits as its factorization.

118113763506181 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2332148570.

The product of its (nonzero) digits is 725760, while the sum is 52.

The spelling of 118113763506181 in words is "one hundred eighteen trillion, one hundred thirteen billion, seven hundred sixty-three million, five hundred six thousand, one hundred eighty-one".