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11813000065 = 52362600013
BaseRepresentation
bin10110000000001110…
…00001001110000001
31010111021020120122221
423000013001032001
5143143112000230
65232105331041
7565510562266
oct130007011601
933437216587
1011813000065
115012148879
122358196a81
1311634ac789
14800c6126d
1549213327a
hex2c01c1381

11813000065 has 4 divisors (see below), whose sum is σ = 14175600084. Its totient is φ = 9450400048.

The previous prime is 11813000047. The next prime is 11813000071. The reversal of 11813000065 is 56000031811.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 56000031811 = 123217454483.

It can be written as a sum of positive squares in 2 ways, for example, as 4893422209 + 6919577856 = 69953^2 + 83184^2 .

It is a cyclic number.

It is not a de Polignac number, because 11813000065 - 29 = 11812999553 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1181300002 + ... + 1181300011.

It is an arithmetic number, because the mean of its divisors is an integer number (3543900021).

Almost surely, 211813000065 is an apocalyptic number.

It is an amenable number.

11813000065 is a deficient number, since it is larger than the sum of its proper divisors (2362600019).

11813000065 is an equidigital number, since it uses as much as digits as its factorization.

11813000065 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2362600018.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 11813000065 its reverse (56000031811), we get a palindrome (67813031876).

The spelling of 11813000065 in words is "eleven billion, eight hundred thirteen million, sixty-five", and thus it is an aban number.

Divisors: 1 5 2362600013 11813000065