1181324347117 has 4 divisors (see below), whose sum is σ = 1182138493536. Its totient is φ = 1180510200700.

The previous prime is 1181324347081. The next prime is 1181324347163. The reversal of 1181324347117 is 7117434231811.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1181324347117 - 2¹⁵ = 1181324314349 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1181324347187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 407071033 + ... + 407073934.

It is an arithmetic number, because the mean of its divisors is an integer number (295534623384).

Almost surely, 2^{1181324347117} is an apocalyptic number.

It is an amenable number.

1181324347117 is a deficient number, since it is larger than the sum of its proper divisors (814146419).

1181324347117 is an equidigital number, since it uses as much as digits as its factorization.

1181324347117 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 814146418.

The product of its digits is 112896, while the sum is 43.

Adding to 1181324347117 its reverse (7117434231811), we get a palindrome (8298758578928).

The spelling of 1181324347117 in words is "one trillion, one hundred eighty-one billion, three hundred twenty-four million, three hundred forty-seven thousand, one hundred seventeen".