11940990853 has 4 divisors (see below), whose sum is σ = 13026535488. Its totient is φ = 10855446220.

The previous prime is 11940990833. The next prime is 11940990869. The reversal of 11940990853 is 35809904911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11940990853 - 2¹³ = 11940982661 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11940990797 and 11940990806.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11940990833) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 542772301 + ... + 542772322.

It is an arithmetic number, because the mean of its divisors is an integer number (3256633872).

Almost surely, 2^11940990853 is an apocalyptic number.

It is an amenable number.

11940990853 is a deficient number, since it is larger than the sum of its proper divisors (1085544635).

11940990853 is a wasteful number, since it uses less digits than its factorization.

11940990853 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1085544634.

The product of its (nonzero) digits is 349920, while the sum is 49.

The spelling of 11940990853 in words is "eleven billion, nine hundred forty million, nine hundred ninety thousand, eight hundred fifty-three".