Base | Representation |
---|---|
bin | 10110001111110011… |
… | …00100001100111001 |
3 | 1010211101011101000100 |
4 | 23013321210030321 |
5 | 143430041103230 |
6 | 5253054430013 |
7 | 601655461515 |
oct | 130771441471 |
9 | 33741141010 |
10 | 11943691065 |
11 | 50799a1969 |
12 | 2393b02309 |
13 | 11845aa927 |
14 | 814361145 |
15 | 49d84b660 |
hex | 2c7e64339 |
11943691065 has 24 divisors (see below), whose sum is σ = 20851346880. Its totient is φ = 6324138144.
The previous prime is 11943691031. The next prime is 11943691069. The reversal of 11943691065 is 56019634911.
It is not a de Polignac number, because 11943691065 - 28 = 11943690809 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a self number, because there is not a number n which added to its sum of digits gives 11943691065.
It is not an unprimeable number, because it can be changed into a prime (11943691069) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 948477 + ... + 960986.
It is an arithmetic number, because the mean of its divisors is an integer number (868806120).
Almost surely, 211943691065 is an apocalyptic number.
11943691065 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11943691065 is a deficient number, since it is larger than the sum of its proper divisors (8907655815).
11943691065 is a wasteful number, since it uses less digits than its factorization.
11943691065 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1909613 (or 1909610 counting only the distinct ones).
The product of its (nonzero) digits is 174960, while the sum is 45.
The spelling of 11943691065 in words is "eleven billion, nine hundred forty-three million, six hundred ninety-one thousand, sixty-five".
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