11952830241 has 27 divisors (see below), whose sum is σ = 18983180307. Its totient is φ = 7241952960.

The previous prime is 11952830231. The next prime is 11952830297. The reversal of 11952830241 is 14203825911.

The square root of 11952830241 is 109329.

It is a perfect power (a square), and thus also a powerful number.

It can be written as a sum of positive squares in only one way, i.e., 11047061025 + 905769216 = 105105^2 + 30096^2 .

It is not a de Polignac number, because 11952830241 - 2²³ = 11944441633 is a prime.

It is a super-3 number, since 3×11952830241³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11952830196 and 11952830205.

It is not an unprimeable number, because it can be changed into a prime (11952830221) by changing a digit.

It is a polite number, since it can be written in 26 ways as a sum of consecutive naturals, for example, 3606201 + ... + 3609513.

Almost surely, 2^11952830241 is an apocalyptic number.

11952830241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

11952830241 is the 109329-th square number.

11952830241 is the 54665-th centered octagonal number.

It is an amenable number.

11952830241 is a deficient number, since it is larger than the sum of its proper divisors (7030350066).

11952830241 is an frugal number, since it uses more digits than its factorization.

11952830241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6654 (or 3327 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 36.

Multiplying 11952830241 by its sum of digits (36), we get a square (430301888676 = 655974²).

It can be divided in two parts, 119528 and 30241, that added together give a square (149769 = 387²).

The spelling of 11952830241 in words is "eleven billion, nine hundred fifty-two million, eight hundred thirty thousand, two hundred forty-one".