Base | Representation |
---|---|
bin | 10110010000111000… |
… | …11011011100010111 |
3 | 1010212000100200120222 |
4 | 23020130123130113 |
5 | 143434411031411 |
6 | 5254022344555 |
7 | 602126244356 |
oct | 131034333427 |
9 | 33760320528 |
10 | 11952830231 |
11 | 50840742a1 |
12 | 2396b8b15b |
13 | 118645a714 |
14 | 81565d99d |
15 | 49e5544db |
hex | 2c871b717 |
11952830231 has 2 divisors, whose sum is σ = 11952830232. Its totient is φ = 11952830230.
The previous prime is 11952830221. The next prime is 11952830297. The reversal of 11952830231 is 13203825911.
It is a weak prime.
It is an emirp because it is prime and its reverse (13203825911) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11952830231 is a prime.
It is a super-2 number, since 2×119528302312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11952830191 and 11952830200.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11952830221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5976415115 + 5976415116.
It is an arithmetic number, because the mean of its divisors is an integer number (5976415116).
Almost surely, 211952830231 is an apocalyptic number.
11952830231 is a deficient number, since it is larger than the sum of its proper divisors (1).
11952830231 is an equidigital number, since it uses as much as digits as its factorization.
11952830231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 35.
The spelling of 11952830231 in words is "eleven billion, nine hundred fifty-two million, eight hundred thirty thousand, two hundred thirty-one".
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