Base | Representation |
---|---|
bin | 1010111000001110101110… |
… | …1110000100001101100111 |
3 | 1120100110210200001012200021 |
4 | 2232003223232010031213 |
5 | 3031432410240024303 |
6 | 41234512404100011 |
7 | 2343110201463250 |
oct | 256035356041547 |
9 | 46313720035607 |
10 | 11961143673703 |
11 | 38a1768860844 |
12 | 1412196994607 |
13 | 689c1456ca33 |
14 | 2d4ccb27bb27 |
15 | 15b20ba49ebd |
hex | ae0ebb84367 |
11961143673703 has 16 divisors (see below), whose sum is σ = 14128547457024. Its totient is φ = 9909237062880.
The previous prime is 11961143673637. The next prime is 11961143673709. The reversal of 11961143673703 is 30737634116911.
It is not a de Polignac number, because 11961143673703 - 221 = 11961141576551 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11961143673709) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 34407025 + ... + 34752922.
It is an arithmetic number, because the mean of its divisors is an integer number (883034216064).
Almost surely, 211961143673703 is an apocalyptic number.
11961143673703 is a deficient number, since it is larger than the sum of its proper divisors (2167403783321).
11961143673703 is an equidigital number, since it uses as much as digits as its factorization.
11961143673703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69160782.
The product of its (nonzero) digits is 1714608, while the sum is 52.
The spelling of 11961143673703 in words is "eleven trillion, nine hundred sixty-one billion, one hundred forty-three million, six hundred seventy-three thousand, seven hundred three".
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