Base | Representation |
---|---|
bin | 110111101110101110… |
… | …0101110101110011011 |
3 | 102102220122221010000022 |
4 | 1233131130232232123 |
5 | 3430100412210042 |
6 | 130551401101055 |
7 | 11434524140600 |
oct | 1573534565633 |
9 | 372818833008 |
10 | 119679413147 |
11 | 468349aa508 |
12 | 1b24048778b |
13 | b39395bcc8 |
14 | 5b149346a7 |
15 | 31a6c7bcd2 |
hex | 1bdd72eb9b |
119679413147 has 6 divisors (see below), whose sum is σ = 139218909228. Its totient is φ = 102582354084.
The previous prime is 119679413137. The next prime is 119679413153. The reversal of 119679413147 is 741314976911.
It is not a de Polignac number, because 119679413147 - 28 = 119679412891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (119679413137) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1221218453 + ... + 1221218550.
It is an arithmetic number, because the mean of its divisors is an integer number (23203151538).
Almost surely, 2119679413147 is an apocalyptic number.
119679413147 is a deficient number, since it is larger than the sum of its proper divisors (19539496081).
119679413147 is an equidigital number, since it uses as much as digits as its factorization.
119679413147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2442437017 (or 2442437010 counting only the distinct ones).
The product of its digits is 1143072, while the sum is 53.
The spelling of 119679413147 in words is "one hundred nineteen billion, six hundred seventy-nine million, four hundred thirteen thousand, one hundred forty-seven".
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