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11968995303 = 323719357593
BaseRepresentation
bin10110010010110100…
…00101111111100111
31010220010202221220100
423021122011333213
5144003030322203
65255401035143
7602413532016
oct131132057747
933803687810
1011968995303
115092205361
1223a0485ab3
1311898ca455
1481786aa7d
154a0b98ea3
hex2c9685fe7

11968995303 has 12 divisors (see below), whose sum is σ = 17293245840. Its totient is φ = 7977162336.

The previous prime is 11968995301. The next prime is 11968995331. The reversal of 11968995303 is 30359986911.

11968995303 is a `hidden beast` number, since 1 + 19 + 6 + 8 + 99 + 530 + 3 = 666.

It is not a de Polignac number, because 11968995303 - 21 = 11968995301 is a prime.

It is a super-4 number, since 4×119689953034 (a number of 41 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11968995303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11968995301) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 145326 + ... + 212267.

It is an arithmetic number, because the mean of its divisors is an integer number (1441103820).

Almost surely, 211968995303 is an apocalyptic number.

11968995303 is a deficient number, since it is larger than the sum of its proper divisors (5324250537).

11968995303 is a wasteful number, since it uses less digits than its factorization.

11968995303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 361318 (or 361315 counting only the distinct ones).

The product of its (nonzero) digits is 1574640, while the sum is 54.

The spelling of 11968995303 in words is "eleven billion, nine hundred sixty-eight million, nine hundred ninety-five thousand, three hundred three".

Divisors: 1 3 9 3719 11157 33471 357593 1072779 3218337 1329888367 3989665101 11968995303