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11981043 = 321331227
BaseRepresentation
bin101101101101…
…000011110011
3211112200220100
4231231003303
511031343133
61104443443
7203560104
oct55550363
924480810
1011981043
116843598
124019583
132636499
14183c3ab
1510b9e13
hexb6d0f3

11981043 has 6 divisors (see below), whose sum is σ = 17305964. Its totient is φ = 7987356.

The previous prime is 11981041. The next prime is 11981059. The reversal of 11981043 is 34018911.

11981043 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11981043 - 21 = 11981041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11980998 and 11981016.

It is not an unprimeable number, because it can be changed into a prime (11981041) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 665605 + ... + 665622.

Almost surely, 211981043 is an apocalyptic number.

11981043 is a deficient number, since it is larger than the sum of its proper divisors (5324921).

11981043 is a wasteful number, since it uses less digits than its factorization.

11981043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1331233 (or 1331230 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 27.

The square root of 11981043 is about 3461.3643263892. The cubic root of 11981043 is about 228.8222274830.

Adding to 11981043 its reverse (34018911), we get a palindrome (45999954).

The spelling of 11981043 in words is "eleven million, nine hundred eighty-one thousand, forty-three".

Divisors: 1 3 9 1331227 3993681 11981043