11981041 has 2 divisors, whose sum is σ = 11981042. Its totient is φ = 11981040.

The previous prime is 11981033. The next prime is 11981059. The reversal of 11981041 is 14018911.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9790641 + 2190400 = 3129^2 + 1480^2 .

It is a cyclic number.

It is not a de Polignac number, because 11981041 - 2³ = 11981033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11980997 and 11981015.

It is not a weakly prime, because it can be changed into another prime (11981341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5990520 + 5990521.

It is an arithmetic number, because the mean of its divisors is an integer number (5990521).

Almost surely, 2^11981041 is an apocalyptic number.

It is an amenable number.

11981041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11981041 is an equidigital number, since it uses as much as digits as its factorization.

11981041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 25.

The square root of 11981041 is about 3461.3640374858. The cubic root of 11981041 is about 228.8222147506.

Adding to 11981041 its reverse (14018911), we get a palindrome (25999952).

The spelling of 11981041 in words is "eleven million, nine hundred eighty-one thousand, forty-one".