11983935 has 8 divisors (see below), whose sum is σ = 19174320. Its totient is φ = 6391424.

The previous prime is 11983901. The next prime is 11983957. The reversal of 11983935 is 53938911.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11983935 - 2¹⁰ = 11982911 is a prime.

It is a super-2 number, since 2×11983935² = 287229396168450, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11983893 and 11983902.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 399450 + ... + 399479.

It is an arithmetic number, because the mean of its divisors is an integer number (2396790).

Almost surely, 2^11983935 is an apocalyptic number.

11983935 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11983935 is a deficient number, since it is larger than the sum of its proper divisors (7190385).

11983935 is an equidigital number, since it uses as much as digits as its factorization.

11983935 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 798937.

The product of its digits is 29160, while the sum is 39.

The square root of 11983935 is about 3461.7820555315. The cubic root of 11983935 is about 228.8406371391.

The spelling of 11983935 in words is "eleven million, nine hundred eighty-three thousand, nine hundred thirty-five".