Base | Representation |
---|---|
bin | 10110010100101100… |
… | …10001001110110011 |
3 | 1010221020110101200022 |
4 | 23022112101032303 |
5 | 144021100114341 |
6 | 5301123114055 |
7 | 602664602216 |
oct | 131226211663 |
9 | 33836411608 |
10 | 11984769971 |
11 | 50a00aa079 |
12 | 23a581292b |
13 | 118cc61585 |
14 | 8199b577d |
15 | 4a2262e4b |
hex | 2ca5913b3 |
11984769971 has 8 divisors (see below), whose sum is σ = 12206642880. Its totient is φ = 11764651392.
The previous prime is 11984769961. The next prime is 11984769997. The reversal of 11984769971 is 17996748911.
11984769971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11984769971 - 218 = 11984507827 is a prime.
It is a super-2 number, since 2×119847699712 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11984769961) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 424790 + ... + 452123.
It is an arithmetic number, because the mean of its divisors is an integer number (1525830360).
Almost surely, 211984769971 is an apocalyptic number.
11984769971 is a deficient number, since it is larger than the sum of its proper divisors (221872909).
11984769971 is an equidigital number, since it uses as much as digits as its factorization.
11984769971 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 877165.
The product of its digits is 6858432, while the sum is 62.
The spelling of 11984769971 in words is "eleven billion, nine hundred eighty-four million, seven hundred sixty-nine thousand, nine hundred seventy-one".
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