Base | Representation |
---|---|
bin | 10110010100101100… |
… | …10001001110110100 |
3 | 1010221020110101200100 |
4 | 23022112101032310 |
5 | 144021100114342 |
6 | 5301123114100 |
7 | 602664602220 |
oct | 131226211664 |
9 | 33836411610 |
10 | 11984769972 |
11 | 50a00aa07a |
12 | 23a5812930 |
13 | 118cc61586 |
14 | 8199b5780 |
15 | 4a2262e4c |
hex | 2ca5913b4 |
11984769972 has 72 divisors (see below), whose sum is σ = 34946323776. Its totient is φ = 3392210304.
The previous prime is 11984769961. The next prime is 11984769997. The reversal of 11984769972 is 27996748911.
11984769972 is a `hidden beast` number, since 1 + 1 + 9 + 8 + 476 + 99 + 72 = 666.
It is a super-2 number, since 2×119847699722 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (63).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 195273 + ... + 249200.
It is an arithmetic number, because the mean of its divisors is an integer number (485365608).
Almost surely, 211984769972 is an apocalyptic number.
11984769972 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11984769972 is an abundant number, since it is smaller than the sum of its proper divisors (22961553804).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11984769972 is a wasteful number, since it uses less digits than its factorization.
11984769972 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 444597 (or 444592 counting only the distinct ones).
The product of its digits is 13716864, while the sum is 63.
The spelling of 11984769972 in words is "eleven billion, nine hundred eighty-four million, seven hundred sixty-nine thousand, nine hundred seventy-two".
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