Base | Representation |
---|---|
bin | 110111110101010111… |
… | …0111110110100110101 |
3 | 102110111012100000100020 |
4 | 1233222232332310311 |
5 | 3431024442121433 |
6 | 131025442235353 |
7 | 11443201514052 |
oct | 1575256766465 |
9 | 373435300306 |
10 | 119902301493 |
11 | 469397a5857 |
12 | 1b2a3055b59 |
13 | b3cab9b2c0 |
14 | 5b36394029 |
15 | 31bb607cb3 |
hex | 1beabbed35 |
119902301493 has 16 divisors (see below), whose sum is σ = 181228850880. Its totient is φ = 69902555904.
The previous prime is 119902301479. The next prime is 119902301501. The reversal of 119902301493 is 394103209911.
It is not a de Polignac number, because 119902301493 - 25 = 119902301461 is a prime.
It is a super-3 number, since 3×1199023014933 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (119902381493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80904996 + ... + 80906477.
It is an arithmetic number, because the mean of its divisors is an integer number (11326803180).
Almost surely, 2119902301493 is an apocalyptic number.
119902301493 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
119902301493 is a deficient number, since it is larger than the sum of its proper divisors (61326549387).
119902301493 is a wasteful number, since it uses less digits than its factorization.
119902301493 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161811508.
The product of its (nonzero) digits is 52488, while the sum is 42.
The spelling of 119902301493 in words is "one hundred nineteen billion, nine hundred two million, three hundred one thousand, four hundred ninety-three".
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