119925443 has 4 divisors (see below), whose sum is σ = 130827768. Its totient is φ = 109023120.

The previous prime is 119925439. The next prime is 119925467. The reversal of 119925443 is 344529911.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 119925443 - 2² = 119925439 is a prime.

It is a super-2 number, since 2×119925443² = 28764223757492498, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 119925397 and 119925406.

It is not an unprimeable number, because it can be changed into a prime (119925413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5451146 + ... + 5451167.

It is an arithmetic number, because the mean of its divisors is an integer number (32706942).

Almost surely, 2^119925443 is an apocalyptic number.

119925443 is a deficient number, since it is larger than the sum of its proper divisors (10902325).

119925443 is a wasteful number, since it uses less digits than its factorization.

119925443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10902324.

The product of its digits is 38880, while the sum is 38.

The square root of 119925443 is about 10951.0475754605. The cubic root of 119925443 is about 493.1402418286.

The spelling of 119925443 in words is "one hundred nineteen million, nine hundred twenty-five thousand, four hundred forty-three".