11994733 has 4 divisors (see below), whose sum is σ = 12013920. Its totient is φ = 11975548.

The previous prime is 11994701. The next prime is 11994751. The reversal of 11994733 is 33749911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33749911 = 13 ⋅2596147.

It is a cyclic number.

It is not a de Polignac number, because 11994733 - 2⁵ = 11994701 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11994692 and 11994701.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11994793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8623 + ... + 9916.

It is an arithmetic number, because the mean of its divisors is an integer number (3003480).

Almost surely, 2^11994733 is an apocalyptic number.

It is an amenable number.

11994733 is a deficient number, since it is larger than the sum of its proper divisors (19187).

11994733 is an equidigital number, since it uses as much as digits as its factorization.

11994733 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19186.

The product of its digits is 20412, while the sum is 37.

The square root of 11994733 is about 3463.3413057335. The cubic root of 11994733 is about 228.9093479982.

The spelling of 11994733 in words is "eleven million, nine hundred ninety-four thousand, seven hundred thirty-three".