11995279994881 has 4 divisors (see below), whose sum is σ = 12055557784000. Its totient is φ = 11935002205764.

The previous prime is 11995279994849. The next prime is 11995279994897. The reversal of 11995279994881 is 18849997259911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11995279994881 - 2⁵ = 11995279994849 is a prime.

It is a super-2 number, since 2×11995279994881² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11995279994795 and 11995279994804.

It is not an unprimeable number, because it can be changed into a prime (11995279994981) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30138894261 + ... + 30138894658.

It is an arithmetic number, because the mean of its divisors is an integer number (3013889446000).

Almost surely, 2^{11995279994881} is an apocalyptic number.

It is an amenable number.

11995279994881 is a deficient number, since it is larger than the sum of its proper divisors (60277789119).

11995279994881 is an equidigital number, since it uses as much as digits as its factorization.

11995279994881 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60277789118.

The product of its digits is 1058158080, while the sum is 82.

The spelling of 11995279994881 in words is "eleven trillion, nine hundred ninety-five billion, two hundred seventy-nine million, nine hundred ninety-four thousand, eight hundred eighty-one".