Base | Representation |
---|---|
bin | 10110010110010110… |
… | …01110011011100111 |
3 | 1010222012120200102112 |
4 | 23023023032123213 |
5 | 144033123332020 |
6 | 5302340431235 |
7 | 603223601051 |
oct | 131313163347 |
9 | 33865520375 |
10 | 11998652135 |
11 | 50a7a20a38 |
12 | 23aa3a851b |
13 | 1192ab2182 |
14 | 81b78a8d1 |
15 | 4a35a62c5 |
hex | 2cb2ce6e7 |
11998652135 has 4 divisors (see below), whose sum is σ = 14398382568. Its totient is φ = 9598921704.
The previous prime is 11998652131. The next prime is 11998652147. The reversal of 11998652135 is 53125689911.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11998652135 - 22 = 11998652131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11998652131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1199865209 + ... + 1199865218.
It is an arithmetic number, because the mean of its divisors is an integer number (3599595642).
Almost surely, 211998652135 is an apocalyptic number.
11998652135 is a deficient number, since it is larger than the sum of its proper divisors (2399730433).
11998652135 is an equidigital number, since it uses as much as digits as its factorization.
11998652135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2399730432.
The product of its digits is 583200, while the sum is 50.
The spelling of 11998652135 in words is "eleven billion, nine hundred ninety-eight million, six hundred fifty-two thousand, one hundred thirty-five".
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