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1200010010114 = 2600005005057
BaseRepresentation
bin10001011101100110001…
…010111001111000000010
311020201102202112200021102
4101131212022321320002
5124130110030310424
62315135455054402
7152461236534026
oct21354612717002
94221382480242
101200010010114
11422a15403913
121746a0b11402
13892116b1056
144211b9b2386
1521335a167ae
hex117662b9e02

1200010010114 has 4 divisors (see below), whose sum is σ = 1800015015174. Its totient is φ = 600005005056.

The previous prime is 1200010010113. The next prime is 1200010010183. The reversal of 1200010010114 is 4110100100021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1065368715889 + 134641294225 = 1032167^2 + 366935^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1200010010095 and 1200010010104.

It is not an unprimeable number, because it can be changed into a prime (1200010010113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300002502527 + ... + 300002502530.

Almost surely, 21200010010114 is an apocalyptic number.

1200010010114 is a deficient number, since it is larger than the sum of its proper divisors (600005005060).

1200010010114 is an equidigital number, since it uses as much as digits as its factorization.

1200010010114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 600005005059.

The product of its (nonzero) digits is 8, while the sum is 11.

Adding to 1200010010114 its reverse (4110100100021), we get a palindrome (5310110110135).

The spelling of 1200010010114 in words is "one trillion, two hundred billion, ten million, ten thousand, one hundred fourteen".

Divisors: 1 2 600005005057 1200010010114