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12000110131 = 18166298951
BaseRepresentation
bin10110010110100001…
…10010011000110011
31010222022022202102101
423023100302120303
5144034012011011
65302432001231
7603242152552
oct131320623063
933868282371
1012000110131
1150a8827399
1223aa990217
1311931a29a9
1481ba49d99
154a37932c1
hex2cb432633

12000110131 has 4 divisors (see below), whose sum is σ = 12066409264. Its totient is φ = 11933811000.

The previous prime is 12000110113. The next prime is 12000110141. The reversal of 12000110131 is 13101100021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13101100021 = 53992426579.

It is a cyclic number.

It is not a de Polignac number, because 12000110131 - 221 = 11998012979 is a prime.

It is a super-2 number, since 2×120001101312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12000110141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33149295 + ... + 33149656.

It is an arithmetic number, because the mean of its divisors is an integer number (3016602316).

Almost surely, 212000110131 is an apocalyptic number.

12000110131 is a deficient number, since it is larger than the sum of its proper divisors (66299133).

12000110131 is an equidigital number, since it uses as much as digits as its factorization.

12000110131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66299132.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 12000110131 its reverse (13101100021), we get a palindrome (25101210152).

The spelling of 12000110131 in words is "twelve billion, one hundred ten thousand, one hundred thirty-one".

Divisors: 1 181 66298951 12000110131