120001113321322 has 4 divisors (see below), whose sum is σ = 180001669981986. Its totient is φ = 60000556660660.

The previous prime is 120001113321307. The next prime is 120001113321389. The reversal of 120001113321322 is 223123311100021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 66386954456761 + 53614158864561 = 8147819^2 + 7322169^2 .

It is a junction number, because it is equal to n+sod(n) for n = 120001113321293 and 120001113321302.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30000278330329 + ... + 30000278330332.

Almost surely, 2^{120001113321322} is an apocalyptic number.

120001113321322 is a deficient number, since it is larger than the sum of its proper divisors (60000556660664).

120001113321322 is an equidigital number, since it uses as much as digits as its factorization.

120001113321322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60000556660663.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 120001113321322 its reverse (223123311100021), we get a palindrome (343124424421343).

The spelling of 120001113321322 in words is "one hundred twenty trillion, one billion, one hundred thirteen million, three hundred twenty-one thousand, three hundred twenty-two".