Base | Representation |
---|---|
bin | 1010111010011111111101… |
… | …1111110111001000100111 |
3 | 1120111012102201001221202111 |
4 | 2232213333133313020213 |
5 | 3033102231312400403 |
6 | 41304441140421451 |
7 | 2345660261465443 |
oct | 256477737671047 |
9 | 46435381057674 |
10 | 12000130200103 |
11 | 39072547230a1 |
12 | 14198573a7887 |
13 | 6907b8678476 |
14 | 2d6b48dd1823 |
15 | 15c23e58d56d |
hex | ae9ff7f7227 |
12000130200103 has 4 divisors (see below), whose sum is σ = 12413927793240. Its totient is φ = 11586332606968.
The previous prime is 12000130200089. The next prime is 12000130200119. The reversal of 12000130200103 is 30100203100021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12000130200103 - 29 = 12000130199591 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12000130200203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 206898796525 + ... + 206898796582.
It is an arithmetic number, because the mean of its divisors is an integer number (3103481948310).
Almost surely, 212000130200103 is an apocalyptic number.
12000130200103 is a deficient number, since it is larger than the sum of its proper divisors (413797593137).
12000130200103 is an equidigital number, since it uses as much as digits as its factorization.
12000130200103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 413797593136.
The product of its (nonzero) digits is 36, while the sum is 13.
Adding to 12000130200103 its reverse (30100203100021), we get a palindrome (42100333300124).
The spelling of 12000130200103 in words is "twelve trillion, one hundred thirty million, two hundred thousand, one hundred three".
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