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120001405343 = 173876901789
BaseRepresentation
bin110111111000010100…
…1000010000110011111
3102110202002211000021012
41233300221002012133
53431230324432333
6131043342325435
711445514054421
oct1576051020637
9373662730235
10120001405343
114698a734a66
121b31028987b
13b415589c31
145b455d0811
1531c5181e48
hex1bf0a4219f

120001405343 has 4 divisors (see below), whose sum is σ = 120008324520. Its totient is φ = 119994486168.

The previous prime is 120001405309. The next prime is 120001405367. The reversal of 120001405343 is 343504100021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120001405343 - 232 = 115706438047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120001405543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3433508 + ... + 3468281.

It is an arithmetic number, because the mean of its divisors is an integer number (30002081130).

Almost surely, 2120001405343 is an apocalyptic number.

120001405343 is a deficient number, since it is larger than the sum of its proper divisors (6919177).

120001405343 is an equidigital number, since it uses as much as digits as its factorization.

120001405343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6919176.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 120001405343 its reverse (343504100021), we get a palindrome (463505505364).

The spelling of 120001405343 in words is "one hundred twenty billion, one million, four hundred five thousand, three hundred forty-three".

Divisors: 1 17387 6901789 120001405343