120001430545303 has 4 divisors (see below), whose sum is σ = 120123507281328. Its totient is φ = 119879353809280.

The previous prime is 120001430545237. The next prime is 120001430545313. The reversal of 120001430545303 is 303545034100021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120001430545303 - 2²⁹ = 120000893674391 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120001430545313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61038366538 + ... + 61038368503.

It is an arithmetic number, because the mean of its divisors is an integer number (30030876820332).

Almost surely, 2^{120001430545303} is an apocalyptic number.

120001430545303 is a deficient number, since it is larger than the sum of its proper divisors (122076736025).

120001430545303 is an equidigital number, since it uses as much as digits as its factorization.

120001430545303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122076736024.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 120001430545303 its reverse (303545034100021), we get a palindrome (423546464645324).

The spelling of 120001430545303 in words is "one hundred twenty trillion, one billion, four hundred thirty million, five hundred forty-five thousand, three hundred three".