12000201311 has 4 divisors (see below), whose sum is σ = 13714515792. Its totient is φ = 10285886832.

The previous prime is 12000201299. The next prime is 12000201341. The reversal of 12000201311 is 11310200021.

12000201311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12000201311 is a prime.

It is a super-2 number, since 2×12000201311² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12000201292 and 12000201301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000201341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 857157230 + ... + 857157243.

It is an arithmetic number, because the mean of its divisors is an integer number (3428628948).

Almost surely, 2^12000201311 is an apocalyptic number.

12000201311 is a deficient number, since it is larger than the sum of its proper divisors (1714314481).

12000201311 is an equidigital number, since it uses as much as digits as its factorization.

12000201311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1714314480.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 12000201311 its reverse (11310200021), we get a palindrome (23310401332).

The spelling of 12000201311 in words is "twelve billion, two hundred one thousand, three hundred eleven".