120002022112121 has 4 divisors (see below), whose sum is σ = 120132601027200. Its totient is φ = 119871443197044.

The previous prime is 120002022112117. The next prime is 120002022112153. The reversal of 120002022112121 is 121211220200021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120002022112121 - 2² = 120002022112117 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 120002022112121.

It is not an unprimeable number, because it can be changed into a prime (120002022112171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65289456161 + ... + 65289457998.

It is an arithmetic number, because the mean of its divisors is an integer number (30033150256800).

Almost surely, 2^{120002022112121} is an apocalyptic number.

It is an amenable number.

120002022112121 is a deficient number, since it is larger than the sum of its proper divisors (130578915079).

120002022112121 is an equidigital number, since it uses as much as digits as its factorization.

120002022112121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130578915078.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 120002022112121 its reverse (121211220200021), we get a palindrome (241213242312142).

The spelling of 120002022112121 in words is "one hundred twenty trillion, two billion, twenty-two million, one hundred twelve thousand, one hundred twenty-one".