12000203333113 has 4 divisors (see below), whose sum is σ = 12007670791680. Its totient is φ = 11992735874548.

The previous prime is 12000203333099. The next prime is 12000203333177. The reversal of 12000203333113 is 31133330200021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12000203333113 - 2²¹ = 12000201235961 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12000203330113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3733726873 + ... + 3733730086.

It is an arithmetic number, because the mean of its divisors is an integer number (3001917697920).

Almost surely, 2^{12000203333113} is an apocalyptic number.

It is an amenable number.

12000203333113 is a deficient number, since it is larger than the sum of its proper divisors (7467458567).

12000203333113 is an equidigital number, since it uses as much as digits as its factorization.

12000203333113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7467458566.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 12000203333113 its reverse (31133330200021), we get a palindrome (43133533533134).

The spelling of 12000203333113 in words is "twelve trillion, two hundred three million, three hundred thirty-three thousand, one hundred thirteen".