120002323133113 has 4 divisors (see below), whose sum is σ = 120004664099328. Its totient is φ = 119999982166900.

The previous prime is 120002323133107. The next prime is 120002323133171. The reversal of 120002323133113 is 311331323200021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120002323133113 - 2¹⁷ = 120002323002041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120002323133513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1170406213 + ... + 1170508738.

It is an arithmetic number, because the mean of its divisors is an integer number (30001166024832).

Almost surely, 2^{120002323133113} is an apocalyptic number.

It is an amenable number.

120002323133113 is a deficient number, since it is larger than the sum of its proper divisors (2340966215).

120002323133113 is an equidigital number, since it uses as much as digits as its factorization.

120002323133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2340966214.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 120002323133113 its reverse (311331323200021), we get a palindrome (431333646333134).

The spelling of 120002323133113 in words is "one hundred twenty trillion, two billion, three hundred twenty-three million, one hundred thirty-three thousand, one hundred thirteen".