Base | Representation |
---|---|
bin | 10001011101100111010… |
… | …111010100110011001101 |
3 | 11020201111011020110200210 |
4 | 101131213113110303031 |
5 | 124130130142341331 |
6 | 2315141452313033 |
7 | 152461602031653 |
oct | 21354727246315 |
9 | 4221434213623 |
10 | 1200030043341 |
11 | 422a257470a8 |
12 | 1746a7772779 |
13 | 892158a662c |
14 | 42120508dd3 |
15 | 21337672446 |
hex | 117675d4ccd |
1200030043341 has 8 divisors (see below), whose sum is σ = 1621958415040. Its totient is φ = 789060850272.
The previous prime is 1200030043301. The next prime is 1200030043349. The reversal of 1200030043341 is 1433400300021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1200030043341 - 210 = 1200030042317 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200030043349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2739794401 + ... + 2739794838.
It is an arithmetic number, because the mean of its divisors is an integer number (202744801880).
Almost surely, 21200030043341 is an apocalyptic number.
It is an amenable number.
1200030043341 is a deficient number, since it is larger than the sum of its proper divisors (421928371699).
1200030043341 is an equidigital number, since it uses as much as digits as its factorization.
1200030043341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5479589315.
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 1200030043341 its reverse (1433400300021), we get a palindrome (2633430343362).
The spelling of 1200030043341 in words is "one trillion, two hundred billion, thirty million, forty-three thousand, three hundred forty-one".
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